0=-2.7t^2+35t+2

Solution for 0=-2.7t^2+35t+2 equation:

0=-2.7t^2+35t+2

We move all terms to the left:

0-(-2.7t^2+35t+2)=0

We add all the numbers together, and all the variables

-(-2.7t^2+35t+2)=0

We get rid of parentheses

2.7t^2-35t-2=0

a = 2.7; b = -35; c = -2;
Δ = b2-4ac
Δ = -352-4·2.7·(-2)
Δ = 1246.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1246.6}}{2*2.7}=\frac{35-\sqrt{1246.6}}{5.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1246.6}}{2*2.7}=\frac{35+\sqrt{1246.6}}{5.4}
$